What is the derivative of 2sin(2cos(x)) ?

The derivative of 2sin(2cos(x)) is -4cos(2cos(x))sin(x)

What is the first derivative of 2sin(2cos(x)) ?

The first derivative of 2sin(2cos(x)) is -4cos(2cos(x))sin(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (2 sin (2 cos (x)))

- 4 cos (2 cos (x)) sin (x)

Solution steps

\frac{d}{d x} (2 sin (2 cos (x)))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (sin (2 cos (x)))

Apply the chain rule:

cos (2 cos (x)) \frac{d}{d x} (2 cos (x))

= cos (2 cos (x)) \frac{d}{d x} (2 cos (x))

\frac{d}{d x} (2 cos (x)) = - 2 sin (x)

= 2 cos (2 cos (x)) (- 2 sin (x))

Simplify

= - 4 cos (2 cos (x)) sin (x)

\frac{d}{d x} (\frac{1}{1 + 4 x ^{2} + x ^{4}})

\int 2 x^{6} - 3 x^{5} + 11 x^{2} + 1 d x

\int (- g t + V) d t

\int e^{9 x} cos (5 x) d x

y = - x^{3} + 2 x

What is the derivative of 2sin(2cos(x)) ?
The derivative of 2sin(2cos(x)) is -4cos(2cos(x))sin(x)
What is the first derivative of 2sin(2cos(x)) ?
The first derivative of 2sin(2cos(x)) is -4cos(2cos(x))sin(x)