What is (\partial)/(\partial x)(cos(xyz)) ?

The answer to (\partial)/(\partial x)(cos(xyz)) is -sin(xyz)yz

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(\partial)/(\partial x)(cos(xyz))

\frac{\partial}{\partial x} (cos (x yz))

- sin (x yz) yz

Solution steps

\frac{\partial}{\partial x} (cos (x yz))

Treat

y, z

as constants

Apply the chain rule:

- sin (x yz) \frac{\partial}{\partial x} (x yz)

= - sin (x yz) \frac{\partial}{\partial x} (x yz)

\frac{\partial}{\partial x} (x yz) = yz

= - sin (x yz) yz

f (x) = \frac{3 x + 2}{5 x - 1}

(x^{5} + 2)^{2} (x^{4} + 4)^{4}

\int_{6}^{7} \frac{x}{x ^{2} - 1} d x

(1 + ln (x) + \frac{y}{x}) d x = (2 - ln (x)) d y

\frac{\partial}{\partial x} (e^{- 3 x - y})

What is (\partial)/(\partial x)(cos(xyz)) ?
The answer to (\partial)/(\partial x)(cos(xyz)) is -sin(xyz)yz