What is the d/(dy)(xe^{xy}) ?

The d/(dy)(xe^{xy}) is e^{xy}x^2

What is the first d/(dy)(xe^{xy}) ?

The first d/(dy)(xe^{xy}) is e^{xy}x^2

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\frac{d}{d y} (x e^{x y})

e^{x y} x^{2}

Solution steps

\frac{d}{d y} (x e^{x y})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{d}{d y} (e^{x y})

Apply the chain rule:

e^{x y} \frac{d}{d y} (x y)

= e^{x y} \frac{d}{d y} (x y)

\frac{d}{d y} (x y) = x

= x e^{x y} x

Simplify

x e^{x y} x : e^{x y} x^{2}

= e^{x y} x^{2}

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