What is the derivative of x^2-3x-4 ?

The derivative of x^2-3x-4 is 2x-3

What is the first derivative of x^2-3x-4 ?

The first derivative of x^2-3x-4 is 2x-3

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\frac{d}{d x} (x^{2} - 3 x - 4)

2 x - 3

Solution steps

\frac{d}{d x} (x^{2} - 3 x - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (3 x) - \frac{d}{d x} (4)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (4) = 0

= 2 x - 3 - 0

Simplify

= 2 x - 3

x \to 0 + lim (e^{\frac{2}{x}})

\int 2 y sin (x) d y

\frac{d y}{d x} = (1 + x) (1 + y)

\int \frac{e ^{- x} sin ^{2} ( x )}{2} d x

x \to 0 lim (\frac{sin ( x )}{4 x})

What is the derivative of x^2-3x-4 ?
The derivative of x^2-3x-4 is 2x-3
What is the first derivative of x^2-3x-4 ?
The first derivative of x^2-3x-4 is 2x-3