What is the normal of y= 2/x ,(1,2) ?

The normal of y= 2/x ,(1,2) is y= 1/2 x+3/2

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normal of y= 2/x ,(1,2)

normal of

y = \frac{2}{x}, (1, 2)

y = \frac{1}{2} x + \frac{3}{2}

Solution steps

Find the slope of

y = \frac{2}{x} : \frac{d y}{d x} = - \frac{2}{x ^{2}}

Compute the slope of

y = \frac{2}{x}

(1, 2) : m = - 2

Compute the slope of the perpendicular line:

m_{p} = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(1, 2) : y = \frac{1}{2} x + \frac{3}{2}

y = \frac{1}{2} x + \frac{3}{2}

\int 6 x + sin (x) d x

\frac{\partial}{\partial y} (2 y^{2} x - 3)

\int x (x + 1)^{3} d x

\frac{d}{d x} (0.5 e^{x - 1})

x \frac{d y}{d x} + y = x y^{2}

What is the normal of y= 2/x ,(1,2) ?
The normal of y= 2/x ,(1,2) is y= 1/2 x+3/2