What is the derivative of x+tan(x) ?

The derivative of x+tan(x) is 1+sec^2(x)

What is the first derivative of x+tan(x) ?

The first derivative of x+tan(x) is 1+sec^2(x)

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\frac{d}{d x} (x + tan (x))

1 + sec^{2} (x)

Solution steps

\frac{d}{d x} (x + tan (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (tan (x))

\frac{d x}{d x} = 1

\frac{d}{d x} (tan (x)) = sec^{2} (x)

= 1 + sec^{2} (x)

\int x^{6} e^{x} d x

(4 x^{2} - 8 x + 8) e^{x}

4 y^{^{''}} + 11 y = 0

\int θ arcsec (6 θ) d θ

\int (\frac{1}{2})^{r^{2}} d θ

What is the derivative of x+tan(x) ?
The derivative of x+tan(x) is 1+sec^2(x)
What is the first derivative of x+tan(x) ?
The first derivative of x+tan(x) is 1+sec^2(x)