What is the limit as x approaches 0 of 4x^2-5x-1 ?

The limit as x approaches 0 of 4x^2-5x-1 is -1

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limit as x approaches 0 of 4x^2-5x-1

x \to 0 lim (4 x^{2} - 5 x - 1)

- 1

Solution steps

x \to 0 lim (4 x^{2} - 5 x - 1)

Plug in the value

x = 0

= 4 \cdot 0^{2} - 5 \cdot 0 - 1

Simplify

= - 1

\frac{\partial}{\partial x} (x \cdot cos (π \cdot x \cdot y^{2}))

\frac{\partial}{\partial t} (3 sin (t))

y^{^{'}} + \frac{2}{t} y = 4 t

\int \frac{1}{x} 1 + \frac{1}{x ^{4}} d x

y^{^{''}} + 4 y^{^{'}} + 3 y = 32 x e^{x}

What is the limit as x approaches 0 of 4x^2-5x-1 ?
The limit as x approaches 0 of 4x^2-5x-1 is -1