What is the d/(dy)(1/(y^2)) ?

The d/(dy)(1/(y^2)) is -2/(y^3)

What is the first d/(dy)(1/(y^2)) ?

The first d/(dy)(1/(y^2)) is -2/(y^3)

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\frac{d}{d y} (\frac{1}{y ^{2}})

- \frac{2}{y ^{3}}

Solution steps

\frac{d}{d y} (\frac{1}{y ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d y} (y^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 2 y^{- 2 - 1}

Simplify

- 2 y^{- 2 - 1} : - \frac{2}{y ^{3}}

= - \frac{2}{y ^{3}}

\int_{0}^{1} x + 1 d x

- csc (x) - cos (x)

x \to 2 lim (h (x))

\int 3 x e^{9 x} d x

\frac{d}{d x} (\frac{50}{x})