What is the integral of 1/(sin^2(x)) ?

The integral of 1/(sin^2(x)) is -cot(x)+C

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integral of 1/(sin^2(x))

\int \frac{1}{sin ^{2} ( x )} d x

- cot (x) + C

Solution steps

\int \frac{1}{sin ^{2} ( x )} d x

Use the common integral:

\int \frac{1}{sin ^{2} ( x )} d x = - cot (x)

= - cot (x)

Add a constant to the solution

= - cot (x) + C

4 y^{^{''}} + 20 y^{^{'}} + 25 y = 0

y = e^{x}, y = 0, x = 0, x = ln (3)

\int e^{x} 8 - e^{x} d x

\frac{d}{d a} (sin^{4} (a) - cos^{4} (a) + cos^{2} (a))

\frac{d}{d x} (x (x + 1))

What is the integral of 1/(sin^2(x)) ?
The integral of 1/(sin^2(x)) is -cot(x)+C