What is the d/(da)(sin^4(a)-cos^4(a)+cos^2(a)) ?

The d/(da)(sin^4(a)-cos^4(a)+cos^2(a)) is 4sin^3(a)cos(a)+4cos^3(a)sin(a)-sin(2a)

What is the first d/(da)(sin^4(a)-cos^4(a)+cos^2(a)) ?

The first d/(da)(sin^4(a)-cos^4(a)+cos^2(a)) is 4sin^3(a)cos(a)+4cos^3(a)sin(a)-sin(2a)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d a} (sin^{4} (a) - cos^{4} (a) + cos^{2} (a))

4 sin^{3} (a) cos (a) + 4 cos^{3} (a) sin (a) - sin (2 a)

Solution steps

\frac{d}{d a} (sin^{4} (a) - cos^{4} (a) + cos^{2} (a))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d a} (sin^{4} (a)) - \frac{d}{d a} (cos^{4} (a)) + \frac{d}{d a} (cos^{2} (a))

\frac{d}{d a} (sin^{4} (a)) = 4 sin^{3} (a) cos (a)

\frac{d}{d a} (cos^{4} (a)) = - 4 cos^{3} (a) sin (a)

\frac{d}{d a} (cos^{2} (a)) = - sin (2 a)

= 4 sin^{3} (a) cos (a) - (- 4 cos^{3} (a) sin (a)) - sin (2 a)

Simplify

= 4 sin^{3} (a) cos (a) + 4 cos^{3} (a) sin (a) - sin (2 a)

\frac{d}{d x} (x (x + 1))

\frac{d}{d x} (4 x^{3} - \frac{2}{x ^{3}})

y^{^{''}} - y^{^{'}} = - 12

\int \frac{4}{( t ^{2} + 1 ) ^{\frac{3}{2}}} d t

\int_{0}^{1} π (x - x^{8}) d x

What is the d/(da)(sin^4(a)-cos^4(a)+cos^2(a)) ?
The d/(da)(sin^4(a)-cos^4(a)+cos^2(a)) is 4sin^3(a)cos(a)+4cos^3(a)sin(a)-sin(2a)
What is the first d/(da)(sin^4(a)-cos^4(a)+cos^2(a)) ?
The first d/(da)(sin^4(a)-cos^4(a)+cos^2(a)) is 4sin^3(a)cos(a)+4cos^3(a)sin(a)-sin(2a)