What is the integral of (e^{-x})/(x^2) ?

The integral of (e^{-x})/(x^2) is -(e^{-x})/x-\Ei(-x)+C

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integral of (e^{-x})/(x^2)

\int \frac{e ^{- x}}{x ^{2}} d x

- \frac{e ^{- x}}{x} - Ei (- x) + C

Solution steps

\int \frac{e ^{- x}}{x ^{2}} d x

Apply Integration By Parts

: - \frac{e ^{- x}}{x} - \int \frac{e ^{- x}}{x} d x

= - \frac{e ^{- x}}{x} - \int \frac{e ^{- x}}{x} d x

\int \frac{e ^{- x}}{x} d x = Ei (- x)

= - \frac{e ^{- x}}{x} - Ei (- x)

Add a constant to the solution

= - \frac{e ^{- x}}{x} - Ei (- x) + C

\int sec^{2} (1) d x

\int_{0}^{1} e^{- s t} (1 - t) d t

\frac{d}{d θ} (4 sin (3 θ))

(2 x + e^{y}) d x + x e^{y} d y = 0

\int t e^{3 t} + e^{t} d t

What is the integral of (e^{-x})/(x^2) ?
The integral of (e^{-x})/(x^2) is -(e^{-x})/x-\Ei(-x)+C