What is (\partial)/(\partial x)(ln(x)+1) ?

The answer to (\partial)/(\partial x)(ln(x)+1) is 1/x

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(\partial)/(\partial x)(ln(x)+1)

\frac{\partial}{\partial x} (ln (x) + 1)

\frac{1}{x}

Solution steps

\frac{\partial}{\partial x} (ln (x) + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (ln (x)) + \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (ln (x)) = \frac{1}{x}

\frac{\partial}{\partial x} (1) = 0

= \frac{1}{x} + 0

Simplify

= \frac{1}{x}

\frac{d}{d x} (ln (x^{- 1}))

\frac{d}{d u} (tan (u))

\int tan^{2} (3 x) d x

\frac{d}{d x} (sin (x^{2 x}))

x \to 5 lim (\frac{∣ x - 5 ∣}{5 - x})

What is (\partial)/(\partial x)(ln(x)+1) ?
The answer to (\partial)/(\partial x)(ln(x)+1) is 1/x