What is the integral of (ln(x^7))/x ?

The integral of (ln(x^7))/x is 7/2 ln^2(x)+C

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integral of (ln(x^7))/x

\int \frac{ln ( x ^{7} )}{x} d x

\frac{7}{2} ln^{2} (x) + C

Solution steps

\int \frac{ln ( x ^{7} )}{x} d x

Apply u-substitution

: \int \frac{ln ( u )}{7 u} d u

= \int \frac{ln ( u )}{7 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{7} \cdot \int \frac{ln ( u )}{u} d u

Apply u-substitution

: \int v d v

= \frac{1}{7} \cdot \int v d v

Apply the Power Rule

: \frac{v ^{2}}{2}

= \frac{1}{7} \cdot \frac{v ^{2}}{2}

Substitute back

= \frac{1}{7} \cdot \frac{ln ^{2} ( x ^{7} )}{2}

Simplify

\frac{1}{7} \cdot \frac{ln ^{2} ( x ^{7} )}{2} : \frac{7}{2} ln^{2} (x)

= \frac{7}{2} ln^{2} (x)

Add a constant to the solution

= \frac{7}{2} ln^{2} (x) + C

h \to 0 lim (h^{2} + h + 1)

y = - x^{2} + 8 x, y = x^{2} - 6 x

\frac{d}{d x} ((x^{2} - 2 x - 1) (\frac{x + 1}{x + 3}))

\int \frac{1}{( 4 - x ) ^{2}} d x

(y) d x - (x + y^{2} - x^{2}) d y = 0

What is the integral of (ln(x^7))/x ?
The integral of (ln(x^7))/x is 7/2 ln^2(x)+C