What is the integral from 3 to 4 of 1/(x^2) ?

The integral from 3 to 4 of 1/(x^2) is 1/12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 3 to 4 of 1/(x^2)

\int_{3}^{4} \frac{1}{x ^{2}} d x

\frac{1}{12}

Decimal Notation

0.08333 \dots

Solution steps

\int_{3}^{4} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{3}^{4}

= [- \frac{1}{x}]_{3}^{4}

Compute the boundaries:

\frac{1}{12}

= \frac{1}{12}

\int x (1 + \frac{1}{x})^{3} d x

x \to + 1 lim (ln (3) + e^{x})

\int \frac{2 x ^{2} + 24}{x ( x - 2 ) ^{3}} d x

\frac{d}{d x} (- x^{2} - 3 x + 4)

\int \frac{1}{a ^{2} - u ^{2}} d u

What is the integral from 3 to 4 of 1/(x^2) ?
The integral from 3 to 4 of 1/(x^2) is 1/12