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شائع >

y^'=(ty^2-1)y

الحلّ

y^{^{'}} = (t y^{2} - 1) y

الحلّ

y = \frac{2}{2 t + 1 + 2 c _{1} e ^{2 t}}, y = - \frac{2}{2 t + 1 + 2 c _{1} e ^{2 t}}

خطوات الحلّ

y^{'} (t) = (t y^{2} - 1) y

Solve Bernoulli ODE:

y = \frac{2}{2 t + 1 + 2 c _{1} e ^{2 t}}, y = - \frac{2}{2 t + 1 + 2 c _{1} e ^{2 t}}

y = \frac{2}{2 t + 1 + 2 c _{1} e ^{2 t}}, y = - \frac{2}{2 t + 1 + 2 c _{1} e ^{2 t}}

أمثلة شائعة

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