What is the integral of 28x^3-18x^2+8x ?

The integral of 28x^3-18x^2+8x is 7x^4-6x^3+4x^2+C

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integral of 28x^3-18x^2+8x

\int 28 x^{3} - 18 x^{2} + 8 x d x

7 x^{4} - 6 x^{3} + 4 x^{2} + C

Solution steps

\int 28 x^{3} - 18 x^{2} + 8 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 28 x^{3} d x - \int 18 x^{2} d x + \int 8 x d x

\int 28 x^{3} d x = 7 x^{4}

\int 18 x^{2} d x = 6 x^{3}

\int 8 x d x = 4 x^{2}

= 7 x^{4} - 6 x^{3} + 4 x^{2}

Add a constant to the solution

= 7 x^{4} - 6 x^{3} + 4 x^{2} + C

\int 5 e^{8 x} d x

(cos (x))^{^{'}}

\int \frac{e ^{x} - e ^{- x}}{e ^{2 x}} d x

x \to 3 lim ([3 (8) (- 10)])

\int \frac{8}{t + 1} + t d t

What is the integral of 28x^3-18x^2+8x ?
The integral of 28x^3-18x^2+8x is 7x^4-6x^3+4x^2+C