What is the tangent of 2x^2+x-1 ?

The tangent of 2x^2+x-1 is y=(4a_{0}+1)x-2a_{0}^2-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of 2x^2+x-1

tangent of

2 x^{2} + x - 1

y = (4 a_{0} + 1) x - 2 a_{0}^{2} - 1

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 2 a_{0}^{2} + a_{0} - 1)

Find the slope of

y = 2 x^{2} + x - 1 : \frac{d y}{d x} = 4 x + 1

Compute the slope of

y = 2 x^{2} + x - 1

x = a_{0} : m = 4 a_{0} + 1

Find the line with slope m=

4 a_{0} + 1

and passing through

(a_{0}, 2 a_{0}^{2} + a_{0} - 1) : y = (4 a_{0} + 1) x - 2 a_{0}^{2} - 1

y = (4 a_{0} + 1) x - 2 a_{0}^{2} - 1

y^{^{''}} + 4 y = 4 cos (2 t)

\int \frac{9}{( 7 x + 4 ) ^{5}} d x

\int 2 x^{2} cos (5 x) d x

y^{^{'}} + 7 y = 5 cos (2 t)

y^{^{''}} - 2 y^{^{'}} + 2 y = 2 x - 2

What is the tangent of 2x^2+x-1 ?
The tangent of 2x^2+x-1 is y=(4a_{0}+1)x-2a_{0}^2-1