y^'+7y=5cos(2t)

Solução

y^{^{'}} + 7 y = 5 cos (2 t)

y = \frac{5 ( 2 sin ( 2 t ) + 7 cos ( 2 t ) )}{53} + \frac{c _{1}}{e ^{7 t}}

Passos da solução

y^{'} (t) + 7 y = 5 cos (2 t)

Solve linear ODE:

y = \frac{5 ( 2 sin ( 2 t ) + 7 cos ( 2 t ) )}{53} + \frac{c _{1}}{e ^{7 t}}

y = \frac{5 ( 2 sin ( 2 t ) + 7 cos ( 2 t ) )}{53} + \frac{c _{1}}{e ^{7 t}}

y^{^{''}} - 2 y^{^{'}} + 2 y = 2 x - 2

x \to 0 + lim (2^{- \frac{1}{x}})

\int \frac{1}{( x ^{2} + y ^{2} + z ^{2} ) ^{\frac{3}{2}}} d x

\int \frac{4 x ^{2} + x + 27}{x ^{3} + 9 x} d x

\frac{\partial}{\partial x} (2 x^{2} - 7 y^{9} - 4)