What is the limit as x approaches 0+of 2^{-1/x} ?

The limit as x approaches 0+of 2^{-1/x} is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0+of 2^{-1/x}

x \to 0 + lim (2^{- \frac{1}{x}})

0

Solution steps

x \to 0 + lim (2^{- \frac{1}{x}})

Apply exponent rules

= x \to 0 + lim (e^{- \frac{1}{x} l n (2)})

Apply the Limit Chain Rule:

0

= 0

\int \frac{1}{( x ^{2} + y ^{2} + z ^{2} ) ^{\frac{3}{2}}} d x

\int \frac{4 x ^{2} + x + 27}{x ^{3} + 9 x} d x

\frac{\partial}{\partial x} (2 x^{2} - 7 y^{9} - 4)

e^{x} sin (x) + e^{x} cos (x)

\int y y^{2} + 1 d y

What is the limit as x approaches 0+of 2^{-1/x} ?
The limit as x approaches 0+of 2^{-1/x} is 0