What is (\partial)/(\partial x)(x^2+xy+3x+2y+5) ?

The answer to (\partial)/(\partial x)(x^2+xy+3x+2y+5) is 2x+y+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(x^2+xy+3x+2y+5)

\frac{\partial}{\partial x} (x^{2} + x y + 3 x + 2 y + 5)

2 x + y + 3

Solution steps

\frac{\partial}{\partial x} (x^{2} + x y + 3 x + 2 y + 5)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (x y) + \frac{\partial}{\partial x} (3 x) + \frac{\partial}{\partial x} (2 y) + \frac{\partial}{\partial x} (5)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (3 x) = 3

\frac{\partial}{\partial x} (2 y) = 0

\frac{\partial}{\partial x} (5) = 0

= 2 x + y + 3 + 0 + 0

Simplify

= 2 x + y + 3

y^{^{''}} + 4 y^{^{'}} + 4 y = - 3 e^{2 t}, y (0) = 1, y^{^{'}} (0) = 0

\frac{\partial}{\partial x} (x^{2} + y^{2} - 1)

f (x) = x^{3} - 7 x^{2} - 7 x + 4

- 9 t

\int sin^{2} (9 x) d x

What is (\partial)/(\partial x)(x^2+xy+3x+2y+5) ?
The answer to (\partial)/(\partial x)(x^2+xy+3x+2y+5) is 2x+y+3