What is the tangent of sqrt(7x+4),\at x=3 ?

The tangent of sqrt(7x+4),\at x=3 is y= 7/10 x+29/10

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tangent of sqrt(7x+4),\at x=3

tangent of

7 x + 4, at x = 3

y = \frac{7}{10} x + \frac{29}{10}

Solution steps

Find the tangent point:

(3, 5)

Find the slope of

y = 7 x + 4 : \frac{d y}{d x} = \frac{7}{2 7 x + 4}

Compute the slope of

y = 7 x + 4

x = 3 : m = \frac{7}{10}

Find the line with slope m=

\frac{7}{10}

and passing through

(3, 5) : y = \frac{7}{10} x + \frac{29}{10}

y = \frac{7}{10} x + \frac{29}{10}

\frac{d}{d x} (- e^{5 x})

\frac{\partial}{\partial y} (x^{2} + y^{2} + x^{2} y + 4)

\int \frac{x ^{2}}{x ^{6} + 1} d x

f (x) = x^{3} - x

\frac{d}{d x} ((x^{2} - 8) (5 x^{3}))

What is the tangent of sqrt(7x+4),\at x=3 ?
The tangent of sqrt(7x+4),\at x=3 is y= 7/10 x+29/10