What is the derivative of f(x)=x^3-x ?

The derivative of f(x)=x^3-x is 3x^2-1

What is the first derivative of f(x)=x^3-x ?

The first derivative of f(x)=x^3-x is 3x^2-1

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derivative of

f (x) = x^{3} - x

3 x^{2} - 1

Solution steps

\frac{d}{d x} (x^{3} - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d x}{d x}

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d x}{d x} = 1

= 3 x^{2} - 1

\frac{d}{d x} ((x^{2} - 8) (5 x^{3}))

\int \frac{cos ( ln ( 2 x ) )}{x} d x

\int \frac{x ^{2} + 16 x - 4}{x ^{3} - 4 x} d x

y = \frac{1}{3 + 2 x}, (2, \frac{1}{7})

7 x - 6 y x^{2} + 1 \frac{d y}{d x} = 0

What is the derivative of f(x)=x^3-x ?
The derivative of f(x)=x^3-x is 3x^2-1
What is the first derivative of f(x)=x^3-x ?
The first derivative of f(x)=x^3-x is 3x^2-1