What is the solution for x(dy)/(dx)=(1-y^2)/(2y) ?

The solution for x(dy)/(dx)=(1-y^2)/(2y) is y=sqrt((-c_{1)+x)/x},y=-sqrt((-c_{1)+x)/x}

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x(dy)/(dx)=(1-y^2)/(2y)

x \frac{d y}{d x} = \frac{1 - y ^{2}}{2 y}

y = \frac{- c _{1} + x}{x}, y = - \frac{- c _{1} + x}{x}

Solution steps

x \frac{d y}{d x} = \frac{1 - y ^{2}}{2 y}

Solve separable ODE:

y = \frac{- c _{1} + x}{x}, y = - \frac{- c _{1} + x}{x}

y = \frac{- c _{1} + x}{x}, y = - \frac{- c _{1} + x}{x}

\int_{0}^{4} \frac{4 t}{( t - 5 ) ^{2}} d t

y^{^{'}} + 4 y = 8

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What is the solution for x(dy)/(dx)=(1-y^2)/(2y) ?
The solution for x(dy)/(dx)=(1-y^2)/(2y) is y=sqrt((-c_{1)+x)/x},y=-sqrt((-c_{1)+x)/x}