What is the derivative of y= 1/(3x^2)-5/(2x) ?

The derivative of y= 1/(3x^2)-5/(2x) is -2/(3x^3)+5/(2x^2)

What is the first derivative of y= 1/(3x^2)-5/(2x) ?

The first derivative of y= 1/(3x^2)-5/(2x) is -2/(3x^3)+5/(2x^2)

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derivative of

y = \frac{1}{3 x ^{2}} - \frac{5}{2 x}

- \frac{2}{3 x ^{3}} + \frac{5}{2 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{3 x ^{2}} - \frac{5}{2 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{3 x ^{2}}) - \frac{d}{d x} (\frac{5}{2 x})

\frac{d}{d x} (\frac{1}{3 x ^{2}}) = - \frac{2}{3 x ^{3}}

\frac{d}{d x} (\frac{5}{2 x}) = - \frac{5}{2 x ^{2}}

= - \frac{2}{3 x ^{3}} - (- \frac{5}{2 x ^{2}})

Simplify

= - \frac{2}{3 x ^{3}} + \frac{5}{2 x ^{2}}

\int \frac{3}{2} t^{2} d t

f (x) = - 3 x^{2} - 2, at x = 5

\int - 4 x e^{x^{2}} d x

\int x sec^{2} (2 x) d x

\frac{3}{( s - 1 ) ^{2}}

What is the derivative of y= 1/(3x^2)-5/(2x) ?
The derivative of y= 1/(3x^2)-5/(2x) is -2/(3x^3)+5/(2x^2)
What is the first derivative of y= 1/(3x^2)-5/(2x) ?
The first derivative of y= 1/(3x^2)-5/(2x) is -2/(3x^3)+5/(2x^2)