What is area f(x)=x^2-2,-3,1 ?

The answer to area f(x)=x^2-2,-3,1 is 4sqrt(2)+(-4sqrt(2)-1)/3+5

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area f(x)=x^2-2,-3,1

area

f (x) = x^{2} - 2, - 3, 1

42 + \frac{- 4 2 - 1}{3} + 5

Solution steps

Apply the area formula:

\int_{- 3}^{1} x^{2} - 2 d x

Solve

\int_{- 3}^{1} x^{2} - 2 d x : 42 + \frac{- 4 2 - 1}{3} + 5

The area is:

= 42 + \frac{- 4 2 - 1}{3} + 5

x y^{^{'''}} + 2 y^{^{''}} = 6 x

\int \frac{x ^{4} + x ^{3} + 2 x + 1}{x ^{2} + x} d x

\frac{d}{d x} (\frac{x ^{2} + 5}{x ^{2} - 1})

\frac{d}{d x} (2 x^{2} + 4 x - 1)

\int_{0}^{1} \frac{61}{4 y - 1} d y

What is area f(x)=x^2-2,-3,1 ?
The answer to area f(x)=x^2-2,-3,1 is 4sqrt(2)+(-4sqrt(2)-1)/3+5