What is the derivative of 2x^2+4x-1 ?

The derivative of 2x^2+4x-1 is 4x+4

What is the first derivative of 2x^2+4x-1 ?

The first derivative of 2x^2+4x-1 is 4x+4

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\frac{d}{d x} (2 x^{2} + 4 x - 1)

4 x + 4

Solution steps

\frac{d}{d x} (2 x^{2} + 4 x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (4 x) - \frac{d}{d x} (1)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (1) = 0

= 4 x + 4 - 0

Simplify

= 4 x + 4

\int_{0}^{1} \frac{61}{4 y - 1} d y

\frac{d y}{d x}, ln (x^{2} - 24 y) = x - y - 4

f (x) = - 2 - 6 x^{2}, (5, - 152)

\int sin (x) cos^{2} (x) d x

\frac{3 s - 4}{s ^{2} + 4 s + 8}

What is the derivative of 2x^2+4x-1 ?
The derivative of 2x^2+4x-1 is 4x+4
What is the first derivative of 2x^2+4x-1 ?
The first derivative of 2x^2+4x-1 is 4x+4