What is the tangent of f(x)=-2-6x^2,(5,-152) ?

The tangent of f(x)=-2-6x^2,(5,-152) is y=-60x+148

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tangent of f(x)=-2-6x^2,(5,-152)

tangent of

f (x) = - 2 - 6 x^{2}, (5, - 152)

y = - 60 x + 148

Solution steps

Find the slope of

f (x) = - 2 - 6 x^{2} : \frac{df ( x )}{d x} = - 12 x

Compute the slope of

f (x) = - 2 - 6 x^{2}

(5, - 152) : m = - 60

Find the line with slope m=

- 60

and passing through

(5, - 152) : y = - 60 x + 148

y = - 60 x + 148

\int sin (x) cos^{2} (x) d x

\frac{3 s - 4}{s ^{2} + 4 s + 8}

\frac{d}{d y} (\frac{y - 6}{y ^{2} - 2 y + 12})

\int (e^{3 x} + 1)^{2} d x

y^{^{''}} + 2 y^{^{'}} - 3 = 0

What is the tangent of f(x)=-2-6x^2,(5,-152) ?
The tangent of f(x)=-2-6x^2,(5,-152) is y=-60x+148