What is the limit as x approaches 0+of 4+ln(x) ?

The limit as x approaches 0+of 4+ln(x) is -infinity

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limit as x approaches 0+of 4+ln(x)

x \to 0 + lim (4 + ln (x))

- \infty

Solution steps

x \to 0 + lim (4 + ln (x))

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 + lim (4) + x \to 0 + lim (ln (x))

x \to 0 + lim (4) = 4

x \to 0 + lim (ln (x)) = - \infty

= 4 - \infty

Apply Infinity Property:

c - \infty = - \infty

= - \infty

e^{x} y \frac{d y}{d x} = e^{- y} + e^{- 5 x - y}

(x^{2} + 8)

f (x) = \frac{x ^{2}}{x ^{2} + x - 2}

\int (x^{2} - 3) sin (2 x) d x

\frac{d}{d x} (sin (x) + sin (y) + sin (x + y))

What is the limit as x approaches 0+of 4+ln(x) ?
The limit as x approaches 0+of 4+ln(x) is -infinity