What is the derivative of 2sqrt(x)-3/(\sqrt[3]{x}) ?

The derivative of 2sqrt(x)-3/(\sqrt[3]{x}) is 1/(sqrt(x))+1/(x^{4/3)}

What is the first derivative of 2sqrt(x)-3/(\sqrt[3]{x}) ?

The first derivative of 2sqrt(x)-3/(\sqrt[3]{x}) is 1/(sqrt(x))+1/(x^{4/3)}

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\frac{1}{x} + \frac{1}{x ^{\frac{4}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (2 x) = \frac{1}{x}

= \frac{1}{x} - (- \frac{1}{x ^{\frac{4}{3}}})

Simplify

= \frac{1}{x} + \frac{1}{x ^{\frac{4}{3}}}

\int \frac{3 x + 11}{x ^{2} - x - 6} d x

y = - 5 x^{\frac{1}{2}} + x^{\frac{3}{2}}

\frac{d y}{d x} = (y^{2} - 1) x

\frac{d}{d x} ((x^{2} + 3 x - 1) e^{x})

\int \frac{2}{3} x^{\frac{3}{2}} - 6 sin (x) + C d x

What is the derivative of 2sqrt(x)-3/(\sqrt[3]{x}) ?
The derivative of 2sqrt(x)-3/(\sqrt[3]{x}) is 1/(sqrt(x))+1/(x^{4/3)}
What is the first derivative of 2sqrt(x)-3/(\sqrt[3]{x}) ?
The first derivative of 2sqrt(x)-3/(\sqrt[3]{x}) is 1/(sqrt(x))+1/(x^{4/3)}