What is the integral of x^3*e^{x^4+5} ?

The integral of x^3*e^{x^4+5} is 1/4 e^{x^4+5}+C

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integral of x^3*e^{x^4+5}

\int x^{3} \cdot e^{x^{4} + 5} d x

\frac{1}{4} e^{x^{4} + 5} + C

Solution steps

\int x^{3} e^{x^{4} + 5} d x

Apply u-substitution

: \int \frac{e ^{u}}{4} d u

= \int \frac{e ^{u}}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{4} e^{u}

Substitute back

u = x^{4} + 5

= \frac{1}{4} e^{x^{4} + 5}

Add a constant to the solution

= \frac{1}{4} e^{x^{4} + 5} + C

(x + (2 x)^{\frac{1}{2}}) (2 x + 1)

\int_{0}^{\frac{π}{2}} sec^{2} (x) d x

\int \frac{x ^{3} + 27}{x + 3} d x

\int fdf

What is the integral of x^3*e^{x^4+5} ?
The integral of x^3*e^{x^4+5} is 1/4 e^{x^4+5}+C