What is the integral from 0 to pi/2 of sec^2(x) ?

The integral from 0 to pi/2 of sec^2(x) is diverges

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integral from 0 to pi/2 of sec^2(x)

\int_{0}^{\frac{π}{2}} sec^{2} (x) d x

diverges

Solution steps

\int_{0}^{\frac{π}{2}} sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= [tan (x)]_{0}^{\frac{π}{2}}

Compute the boundaries:

diverges

= diverges

\int \frac{x ^{3} + 27}{x + 3} d x

\int fdf

\int_{\frac{π}{4}}^{π} sin (x) d x

\frac{d}{d x} (cos^{4} (x) + sec (x^{3}))

What is the integral from 0 to pi/2 of sec^2(x) ?
The integral from 0 to pi/2 of sec^2(x) is diverges