What is the integral from pi/4 to pi of sin(x) ?

The integral from pi/4 to pi of sin(x) is 1+1/(sqrt(2))

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integral from pi/4 to pi of sin(x)

\int_{\frac{π}{4}}^{π} sin (x) d x

1 + \frac{1}{2}

Solution steps

\int_{\frac{π}{4}}^{π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{\frac{π}{4}}^{π}

Compute the boundaries:

1 + \frac{1}{2}

= 1 + \frac{1}{2}

\frac{d}{d x} (cos^{4} (x) + sec (x^{3}))

\int cos (x) d x

\int \frac{1}{x ^{2} + z ^{2}} d x

f (x) = 4 x + 1

\frac{d y}{d t} - (\frac{3}{t}) y = 2 t^{3} e^{2 t}

What is the integral from pi/4 to pi of sin(x) ?
The integral from pi/4 to pi of sin(x) is 1+1/(sqrt(2))