What is the solution for (dy)/(dt)-(3/t)y=2t^3e^{2t} ?

The solution for (dy)/(dt)-(3/t)y=2t^3e^{2t} is y=e^{2t}t^3+c_{1}t^3

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(dy)/(dt)-(3/t)y=2t^3e^{2t}

\frac{d y}{d t} - (\frac{3}{t}) y = 2 t^{3} e^{2 t}

y = e^{2 t} t^{3} + c_{1} t^{3}

Solution steps

\frac{d y}{d t} - (\frac{3}{t}) y = 2 t^{3} e^{2 t}

Solve linear ODE:

y = e^{2 t} t^{3} + c_{1} t^{3}

y = e^{2 t} t^{3} + c_{1} t^{3}

\frac{\partial}{\partial x} (cos (5 x - 2 y^{2}))

x^{2} + 8

n = 1 \sum \infty \frac{1}{4 n ^{6} + n + 1}

\frac{d y}{d x} = \frac{9 x}{y}

\int (\frac{1}{x \cdot ln ( x )}) d x

What is the solution for (dy)/(dt)-(3/t)y=2t^3e^{2t} ?
The solution for (dy)/(dt)-(3/t)y=2t^3e^{2t} is y=e^{2t}t^3+c_{1}t^3