What is the derivative of (2x-1^4) ?

The derivative of (2x-1^4) is 8(2x-1)^3

What is the first derivative of (2x-1^4) ?

The first derivative of (2x-1^4) is 8(2x-1)^3

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\frac{d}{d x} ((2 x - 1)^{4})

8 (2 x - 1)^{3}

Solution steps

\frac{d}{d x} ((2 x - 1)^{4})

Apply the chain rule:

4 (2 x - 1)^{3} \frac{d}{d x} (2 x - 1)

= 4 (2 x - 1)^{3} \frac{d}{d x} (2 x - 1)

\frac{d}{d x} (2 x - 1) = 2

= 4 (2 x - 1)^{3} \cdot 2

Simplify

= 8 (2 x - 1)^{3}

\int \frac{x ^{2}}{( x ^{3} - 1 ) ^{4}} d x

\int 9 sin^{- \frac{3}{2}} (x) cos^{3} (x) d x

y^{^{''}} + 7 y^{^{'}} + 6 y = 0

x \to 1 lim (x - 8)

\frac{d}{d x} (\frac{x ^{3}}{x ^{2} + 1})

What is the derivative of (2x-1^4) ?
The derivative of (2x-1^4) is 8(2x-1)^3
What is the first derivative of (2x-1^4) ?
The first derivative of (2x-1^4) is 8(2x-1)^3