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Popular >

derivative of y=(x^4)/4+1/(8x^2)

Solution

derivative of

y = \frac{x ^{4}}{4} + \frac{1}{8 x ^{2}}

Solution

x^{3} - \frac{1}{4 x ^{3}}

Solution steps

\frac{d}{d x} (\frac{x ^{4}}{4} + \frac{1}{8 x ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{4}}{4}) + \frac{d}{d x} (\frac{1}{8 x ^{2}})

\frac{d}{d x} (\frac{x ^{4}}{4}) = x^{3}

\frac{d}{d x} (\frac{1}{8 x ^{2}}) = - \frac{1}{4 x ^{3}}

= x^{3} - \frac{1}{4 x ^{3}}

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Frequently Asked Questions (FAQ)

What is the derivative of y=(x^4)/4+1/(8x^2) ?
The derivative of y=(x^4)/4+1/(8x^2) is x^3-1/(4x^3)
What is the first derivative of y=(x^4)/4+1/(8x^2) ?
The first derivative of y=(x^4)/4+1/(8x^2) is x^3-1/(4x^3)