What is the derivative of (2x+3)^2 ?

The derivative of (2x+3)^2 is 4(2x+3)

What is the first derivative of (2x+3)^2 ?

The first derivative of (2x+3)^2 is 4(2x+3)

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derivative of

(2 x + 3)^{2}

4 (2 x + 3)

Solution steps

\frac{d}{d x} ((2 x + 3)^{2})

Apply the chain rule:

2 (2 x + 3) \frac{d}{d x} (2 x + 3)

= 2 (2 x + 3) \frac{d}{d x} (2 x + 3)

\frac{d}{d x} (2 x + 3) = 2

= 2 (2 x + 3) \cdot 2

Simplify

= 4 (2 x + 3)

4 x^{2} (\frac{d y}{d x}) = (\frac{d y}{d x}) + 3 x e^{- y}

\frac{d}{d x} (- x^{2} y^{2})

x \to 0 lim (x cos (\frac{14}{x}))

x \to 1 - lim (3 x - 2)

\frac{\partial}{\partial u} (u + v)

What is the derivative of (2x+3)^2 ?
The derivative of (2x+3)^2 is 4(2x+3)
What is the first derivative of (2x+3)^2 ?
The first derivative of (2x+3)^2 is 4(2x+3)