What is (\partial)/(\partial u)(u+v) ?

The answer to (\partial)/(\partial u)(u+v) is 1

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(\partial)/(\partial u)(u+v)

\frac{\partial}{\partial u} (u + v)

1

Solution steps

\frac{\partial}{\partial u} (u + v)

Treat

v

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial u} (u) + \frac{\partial}{\partial u} (v)

\frac{\partial}{\partial u} (u) = 1

\frac{\partial}{\partial u} (v) = 0

= 1 + 0

Simplify

= 1

\int \frac{x ^{2}}{2} \frac{1}{x} d x

t^{2} \cdot sin (3 t)

\int (2 t + 3)^{- 2} d t

x e^{y} \frac{d y}{d x} + e^{y} = e^{x}

\frac{d}{d x} (e^{- \frac{x}{2}} sin (\frac{3}{2} x))

What is (\partial)/(\partial u)(u+v) ?
The answer to (\partial)/(\partial u)(u+v) is 1