What is inverse oflaplace 3/((s+2)) ?

The answer to inverse oflaplace 3/((s+2)) is 3e^{-2t}

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inverse oflaplace 3/((s+2))

inverse laplace

\frac{3}{( s + 2 )}

3 e^{- 2 t}

Solution steps

L^{- 1} {\frac{3}{( s + 2 )}}

= L^{- 1} {3 \cdot \frac{1}{s + 2}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 3 L^{- 1} {\frac{1}{s + 2}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s + 2}} = e^{- 2 t}

= 3 e^{- 2 t}

y^{^{''}} + 2 y^{^{'}} + 2 y = e^{- t} cos (t)

\frac{d}{d x} (ln (e^{s i n (x)} \cdot x^{c o s (x)}))

x \to - 1 lim (x^{3} + 3 x^{2} - 2 x - 3)

t y^{^{'}} + 4 y = t^{3}, y (2) = 4

\frac{d}{d x} (\frac{w}{1 - 4 x ^{2}})

What is inverse oflaplace 3/((s+2)) ?
The answer to inverse oflaplace 3/((s+2)) is 3e^{-2t}