What is the derivative of (e^{x^2}/(2x)) ?

The derivative of (e^{x^2}/(2x)) is (2e^{x^2}x^2-e^{x^2})/(2x^2)

What is the first derivative of (e^{x^2}/(2x)) ?

The first derivative of (e^{x^2}/(2x)) is (2e^{x^2}x^2-e^{x^2})/(2x^2)

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\frac{d}{d x} (\frac{e ^{x^{2}}}{2 x})

\frac{2 e ^{x^{2}} x ^{2} - e ^{x^{2}}}{2 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{e ^{x^{2}}}{2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (\frac{e ^{x^{2}}}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{2} \cdot \frac{\frac{d}{d x} ( e ^{x^{2}} ) x - \frac{d x}{d x} e ^{x^{2}}}{x ^{2}}

\frac{d}{d x} (e^{x^{2}}) = e^{x^{2}} \cdot 2 x

\frac{d x}{d x} = 1

= \frac{1}{2} \cdot \frac{e ^{x^{2}} \cdot 2 xx - 1 \cdot e ^{x^{2}}}{x ^{2}}

Simplify

\frac{1}{2} \cdot \frac{e ^{x^{2}} \cdot 2 xx - 1 \cdot e ^{x^{2}}}{x ^{2}} : \frac{2 e ^{x^{2}} x ^{2} - e ^{x^{2}}}{2 x ^{2}}

= \frac{2 e ^{x^{2}} x ^{2} - e ^{x^{2}}}{2 x ^{2}}

\int_{1}^{2} (x - x) d x

\frac{d}{d x} (e^{- x^{2} - y^{2}})

\int arccsc (x) d x

n = 1 \sum \infty \frac{x ^{n}}{n + 5}

\frac{\partial}{\partial x} (7 x y^{4} + 2)

What is the derivative of (e^{x^2}/(2x)) ?
The derivative of (e^{x^2}/(2x)) is (2e^{x^2}x^2-e^{x^2})/(2x^2)
What is the first derivative of (e^{x^2}/(2x)) ?
The first derivative of (e^{x^2}/(2x)) is (2e^{x^2}x^2-e^{x^2})/(2x^2)