What is the derivative of x^2-xy ?

The derivative of x^2-xy is 2x-y-x(dy)/(dx)

What is the first derivative of x^2-xy ?

The first derivative of x^2-xy is 2x-y-x(dy)/(dx)

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\frac{d}{d x} (x^{2} - x y)

2 x - y - x \frac{d y}{d x}

Solution steps

\frac{d}{d x} (x^{2} - x y)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (x y)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (x y) = y + x \frac{d y}{d x}

= 2 x - (y + x \frac{d y}{d x})

Simplify

= 2 x - y - x \frac{d y}{d x}

y^{^{'}} = 1 + x^{2} + y^{2} + x^{2} y^{2}

\int_{0}^{1} \frac{y}{e ^{2 y}} d y

\frac{\partial}{\partial y} (x y^{3} z^{2})

\frac{d}{d x} (x^{2} - \frac{2}{x ^{2}})

\frac{\partial}{\partial x} (x \cdot Y (x))

What is the derivative of x^2-xy ?
The derivative of x^2-xy is 2x-y-x(dy)/(dx)
What is the first derivative of x^2-xy ?
The first derivative of x^2-xy is 2x-y-x(dy)/(dx)