What is the tangent of f(x)=x^2+7 ?

The tangent of f(x)=x^2+7 is y=2a_{0}x-a_{0}^2+7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=x^2+7

tangent of

f (x) = x^{2} + 7

y = 2 a_{0} x - a_{0}^{2} + 7

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0}^{2} + 7)

Find the slope of

f (x) = x^{2} + 7 : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2} + 7

x = a_{0} : m = 2 a_{0}

Find the line with slope m=

2 a_{0}

and passing through

(a_{0}, a_{0}^{2} + 7) : y = 2 a_{0} x - a_{0}^{2} + 7

y = 2 a_{0} x - a_{0}^{2} + 7

\frac{\partial}{\partial x} (2 e^{\frac{x}{2} + y})

\int + x^{2} e^{4 x} d x

y^{^{''}} + 16 y = e^{- t}

\frac{\partial}{\partial x} (e^{- x} cos (x))

9 y ln (x) - x y^{^{'}} = 0

What is the tangent of f(x)=x^2+7 ?
The tangent of f(x)=x^2+7 is y=2a_{0}x-a_{0}^2+7