What is (\partial)/(\partial z)(5e^xcos(yz)) ?

The answer to (\partial)/(\partial z)(5e^xcos(yz)) is -5e^xysin(yz)

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(\partial)/(\partial z)(5e^xcos(yz))

\frac{\partial}{\partial z} (5 e^{x} cos (yz))

- 5 e^{x} y sin (yz)

Solution steps

\frac{\partial}{\partial z} (5 e^{x} cos (yz))

Treat

x, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 e^{x} \frac{\partial}{\partial z} (cos (yz))

Apply the chain rule:

- sin (yz) \frac{\partial}{\partial z} (yz)

= - sin (yz) \frac{\partial}{\partial z} (yz)

\frac{\partial}{\partial z} (yz) = y

= 5 e^{x} (- sin (yz) y)

Simplify

= - 5 e^{x} y sin (yz)

- \frac{9}{x ^{2}}

0.8 x + 19, \frac{355.6}{x + 6}

x \to 0 lim ((1 - 7 x)^{\frac{4}{x}})

\int_{- 1}^{3} (3 x^{2} - 5) d x

\int_{- 2}^{3} f (x) d x

What is (\partial)/(\partial z)(5e^xcos(yz)) ?
The answer to (\partial)/(\partial z)(5e^xcos(yz)) is -5e^xysin(yz)