What is the limit as x approaches 0 of (1-7x)^{4/x} ?

The limit as x approaches 0 of (1-7x)^{4/x} is 1/(e^{28)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of (1-7x)^{4/x}

x \to 0 lim ((1 - 7 x)^{\frac{4}{x}})

\frac{1}{e ^{28}}

Solution steps

x \to 0 lim ((1 - 7 x)^{\frac{4}{x}})

Apply exponent rules

= x \to 0 lim (e^{\frac{4}{x} l n (1 - 7 x)})

Apply the Limit Chain Rule:

\frac{1}{e ^{28}}

= \frac{1}{e ^{28}}

\int_{- 1}^{3} (3 x^{2} - 5) d x

\int_{- 2}^{3} f (x) d x

n = 0 \sum \infty \frac{( x ) ^{n}}{n !}

4 x \frac{d y}{d x} - 8 y = x^{- 9}

- 3 x (5 x + 4)^{6}

What is the limit as x approaches 0 of (1-7x)^{4/x} ?
The limit as x approaches 0 of (1-7x)^{4/x} is 1/(e^{28)}