What is the solution for 4x(dy)/(dx)-8y=x^{-9} ?

The solution for 4x(dy)/(dx)-8y=x^{-9} is y=-1/(44x^9)+c_{1}x^2

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4x(dy)/(dx)-8y=x^{-9}

4 x \frac{d y}{d x} - 8 y = x^{- 9}

y = - \frac{1}{44 x ^{9}} + c_{1} x^{2}

Solution steps

4 x \frac{d y}{d x} - 8 y = x^{- 9}

Solve linear ODE:

y = - \frac{1}{44 x ^{9}} + c_{1} x^{2}

y = - \frac{1}{44 x ^{9}} + c_{1} x^{2}

- 3 x (5 x + 4)^{6}

\int 13 x d x

f (t) = e^{6 t s i n (2 t)}

y^{^{''}} - 8 y^{^{'}} - 9 y = 0

\frac{d}{d x} (- i e^{- i x})

What is the solution for 4x(dy)/(dx)-8y=x^{-9} ?
The solution for 4x(dy)/(dx)-8y=x^{-9} is y=-1/(44x^9)+c_{1}x^2