What is (\partial)/(\partial z)((x-y)/(y+z)) ?

The answer to (\partial)/(\partial z)((x-y)/(y+z)) is -(x-y)/((y+z)^2)

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(\partial)/(\partial z)((x-y)/(y+z))

\frac{\partial}{\partial z} (\frac{x - y}{y + z})

- \frac{x - y}{( y + z ) ^{2}}

Solution steps

\frac{\partial}{\partial z} (\frac{x - y}{y + z})

Treat

x, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= (x - y) \frac{\partial}{\partial z} (\frac{1}{y + z})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= (x - y) \frac{\partial}{\partial z} ((y + z)^{- 1})

Apply the chain rule:

- \frac{1}{( y + z ) ^{2}} \frac{\partial}{\partial z} (y + z)

= - \frac{1}{( y + z ) ^{2}} \frac{\partial}{\partial z} (y + z)

\frac{\partial}{\partial z} (y + z) = 1

= (x - y) (- \frac{1}{( y + z ) ^{2}} \cdot 1)

Simplify

(x - y) (- \frac{1}{( y + z ) ^{2}} \cdot 1) : - \frac{x - y}{( y + z ) ^{2}}

= - \frac{x - y}{( y + z ) ^{2}}

\int (e^{t} + t^{e}) d t

\frac{2}{x}, 8 x, \frac{x}{2}

\frac{\partial}{\partial x} (e^{x + x y - 2 y})

\int_{0}^{0.5} 600 x d x

f (x) = 5 x^{2} - 6 x + 6 + ln (x)

What is (\partial)/(\partial z)((x-y)/(y+z)) ?
The answer to (\partial)/(\partial z)((x-y)/(y+z)) is -(x-y)/((y+z)^2)