What is the limit as x approaches 0 of ((1+x)^5-1)/x ?

The limit as x approaches 0 of ((1+x)^5-1)/x is 5

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limit as x approaches 0 of ((1+x)^5-1)/x

x \to 0 lim (\frac{( 1 + x ) ^{5} - 1}{x})

5

Solution steps

x \to 0 lim (\frac{( 1 + x ) ^{5} - 1}{x})

Simplify

\frac{( 1 + x ) ^{5} - 1}{x} : x + (x + 1)^{4} + (x + 1)^{3} + (x + 1)^{2} + 2

= x \to 0 lim (x + (x + 1)^{4} + (x + 1)^{3} + (x + 1)^{2} + 2)

Plug in the value

x = 0

= 0 + (0 + 1)^{4} + (0 + 1)^{3} + (0 + 1)^{2} + 2

Simplify

0 + (0 + 1)^{4} + (0 + 1)^{3} + (0 + 1)^{2} + 2 : 5

= 5

y \to - 3 lim (lo g_{2} (3) y^{2})

\int \frac{r ^{3}}{1 + r ^{2}} d r

\int_{0}^{4} x 4 - x d x

x \to \infty lim (\frac{( x + 1 ) ^{2} e ^{x^{3}}}{e ^{(x + 1)^{3}} x ^{2}})

x \to 16 - lim (\frac{8}{11 + 2 ^{\frac{1}{x - 16}}})

What is the limit as x approaches 0 of ((1+x)^5-1)/x ?
The limit as x approaches 0 of ((1+x)^5-1)/x is 5