What is (\partial)/(\partial x)(sin(8pit+9x)) ?

The answer to (\partial)/(\partial x)(sin(8pit+9x)) is cos(8pit+9x)*9

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(\partial)/(\partial x)(sin(8pit+9x))

\frac{\partial}{\partial x} (sin (8 π t + 9 x))

cos (8 π t + 9 x) \cdot 9

Solution steps

\frac{\partial}{\partial x} (sin (8 π t + 9 x))

Treat

t

as a constant

Apply the chain rule:

cos (8 π t + 9 x) \frac{\partial}{\partial x} (8 π t + 9 x)

= cos (8 π t + 9 x) \frac{\partial}{\partial x} (8 π t + 9 x)

\frac{\partial}{\partial x} (8 π t + 9 x) = 9

= cos (8 π t + 9 x) \cdot 9

\frac{\partial}{\partial x} (x^{2} + 10 x yz + y^{2} + 8 z^{2})

\frac{d}{d x} (arctanh (cos (x)))

\frac{d}{d x} (x - 3 y)

e^{- 2 x^{2}}

x = - y^{2} + 2, x = y^{2} - 4

What is (\partial)/(\partial x)(sin(8pit+9x)) ?
The answer to (\partial)/(\partial x)(sin(8pit+9x)) is cos(8pit+9x)*9