What is area x=-y^2+2,x=y^2-4 ?

The answer to area x=-y^2+2,x=y^2-4 is No Solution

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area x=-y^2+2,x=y^2-4

area

x = - y^{2} + 2, x = y^{2} - 4

No Solution

Solution steps

Isolate

y

for

x = - y^{2} + 2 : y = - x + 2, y = - - x + 2

Isolate

y

for

x = y^{2} - 4 : y = x + 4, y = - x + 4

f_{1} (x) = - x + 2

f_{2} (x) = - - x + 2

To find the intersection points solve

f_{i} (x) = f_{j} (x)

- x + 2 = - - x + 2 : x = 2

- x + 2 = x + 4 : x = - 1

- x + 2 = - x + 4 :

No Solution for

x \in R

- - x + 2 = x + 4 :

No Solution for

x \in R

- - x + 2 = - x + 4 : x = - 1

x + 4 = - x + 4 : x = - 4

Curves not bounded

= No Solution

\int_{- 2}^{3} \frac{42}{x ^{4}} d x

\frac{d}{d x} (8 x - \frac{3}{x})

\frac{d}{d t} (5^{2 t})

\frac{d}{d x} (a e^{2 x})

\frac{1}{x ^{5}} + \frac{2}{x ^{9}}

What is area x=-y^2+2,x=y^2-4 ?
The answer to area x=-y^2+2,x=y^2-4 is No Solution