What is the derivative of f(x)=ln(3+x) ?

The derivative of f(x)=ln(3+x) is 1/(3+x)

What is the first derivative of f(x)=ln(3+x) ?

The first derivative of f(x)=ln(3+x) is 1/(3+x)

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derivative of

f (x) = ln (3 + x)

\frac{1}{3 + x}

Solution steps

\frac{d}{d x} (ln (3 + x))

Apply the chain rule:

\frac{1}{3 + x} \frac{d}{d x} (3 + x)

= \frac{1}{3 + x} \frac{d}{d x} (3 + x)

\frac{d}{d x} (3 + x) = 1

= \frac{1}{3 + x} \cdot 1

Simplify

= \frac{1}{3 + x}

y^{^{'}} = y + 1

\int_{3}^{3} \frac{1}{9 + x ^{2}} d x

\int_{- \infty}^{0} \frac{1}{3 - 9 x} d x

\frac{d}{d x} ((f (x))^{2})

\frac{d}{d y} (1 - 2 y)

What is the derivative of f(x)=ln(3+x) ?
The derivative of f(x)=ln(3+x) is 1/(3+x)
What is the first derivative of f(x)=ln(3+x) ?
The first derivative of f(x)=ln(3+x) is 1/(3+x)