What is the integral from-infinity to 0 of 1/(3-9x) ?

The integral from-infinity to 0 of 1/(3-9x) is diverges

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integral from-infinity to 0 of 1/(3-9x)

\int_{- \infty}^{0} \frac{1}{3 - 9 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{3 - 9 x} d x

Compute the indefinite integral:

\int \frac{1}{3 - 9 x} d x = - \frac{1}{9} ln ∣ 3 - 9 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{3 - 9 x} d x =

diverges

= diverges

\frac{d}{d x} ((f (x))^{2})

\frac{d}{d y} (1 - 2 y)

\int \frac{ln ( x ^{2} )}{2 x} d x

y = 3 x^{2} + 14 x - 5

\frac{d y}{d x} = \frac{1}{10} y - \frac{1}{5000} y^{2}, y (0) = 50

What is the integral from-infinity to 0 of 1/(3-9x) ?
The integral from-infinity to 0 of 1/(3-9x) is diverges